x-9/x^3+6x=0

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Solution for x-9/x^3+6x=0 equation: 


D( x )

x^3 = 0

x^3 = 0

x^3 = 0

1*x^3 = 0 // : 1

x^3 = 0

x = 0

x in (-oo:0) U (0:+oo)

x+6*x-(9/(x^3)) = 0

x+6*x-9*x^-3 = 0

7*x-9*x^-3 = 0

x*(7-9*x^-4) = 0

-9*x^-4 = -7 // : -9

x^-4 = 7/9

-4 < 0

1/(x^4) = 7/9 // * x^4

1 = 7/9*x^4 // : 7/9

9/7 = x^4

x^4 = 9/7 // ^ 1/4

abs(x) = (9/7)^(1/4)

x = (9/7)^(1/4) or x = -(9/7)^(1/4)

x = 0

x = 0

x in { 0} 

x in { (9/7)^(1/4), -(9/7)^(1/4) }

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